General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 1 Chemistry and the Scientific Method - Problems - Page 35: 27



Work Step by Step

First: $$\text{average value}=\frac{153.2\text{ mg}+151.1\text{ mg}+152.0\text{ mg}+146.9\text{ mg}+149.8\text{ mg}}{5}=150.6\text{ mg}$$ From this we can get: $$\text{percentage error}=\frac{150.6\text{mg}-150\text{ mg}}{150\text{ mg}}\cdot 100=0.4\%$$
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