Answer
(b) and (d) might be found at equilibrium.
Work Step by Step
(a) It is impossible to have all these pressures with the same value, because if so:
$$K_p = \frac{P_{CO_2}P_{H_2}}{P_{CO}P_{H_2O}} = 1$$
And, as we know, Kp is not equal to 1.
False
(c) Substitute:
$$K_p = \frac{P_{CO}P_{H_2O}}{P_{CO}P_{H_2O}} = 1$$
And, as we know, Kp is not equal to 1.
False
- The other two alternatives (b) and (d) are possible, since we cannot do the same substitutions and have a False result.
