## General Chemistry: Principles and Modern Applications (10th Edition)

d = 5.56* $10^{-3}$ mm
V = 90.0 * $10^{-12}$ $cm^{3}$ V of sphere = $\frac{4}{3} * π * r^{3}$ $\frac{4}{3} * π * r^{3}$ = 90.0 * $10^{-12}$ $π * r^{3}$ = $\frac{3}{4}$ * 90.0 * $10^{-12}$ $π * r^{3}$ = $6.75 * 10^{-11}$ $r^{3}$ = $\frac{6.75 * 10^{-11}}{π}$ r = $\sqrt[3] \frac{6.75 * 10^{-11}}{π}$ r = 2.780041634 * $10^{-4}$ cm d = 2 * r d = 2 * 2.780041634 * $10^{-4}$ cm = 5.560083268 * $10^{-4}$ cm d = 5.560083268 * $10^{-3}$ mm Rounding to 3 significant figures gives d = 5.56* $10^{-3}$ mm