General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Units of Measurement - Page 28: 39

Answer

pressure = 2.2 * $10^{3}$ g / $cm^{2}$ pressure = 2.2 * $10^{4}$ kg / $m^{2}$

Work Step by Step

pressure = 32 lb per 1 $in^{2}$ 1 in = 2.54 cm 1 $in^{2}$ = 2.54 cm * 2.54 cm = 6.4516 $cm^{2}$ so pressure = 32 lb per 6.4516 $cm^{2}$ 2.205 lb = 1 kg 2.205 lb = 1000 g 1 lb = 1000 / 2.205 g = 453.5147392 g 32 lb = 32 * 453.5147392 g = 14512.47165 g so pressure = 14512.47165 g per 6.4516 $cm^{2}$ pressure = 2249.437605 g per 1 $cm^{2}$ pressure = 2249.437605 g / $cm^{2}$ rounding to 2 significant figures gives 2.2 * $10^{3 }$ g / $cm^{2}$ pressure = 2249.437605 g per 1 $cm^{2}$ 2249.437605 g = 2249.437605 / 1000 kg = 2.249437605 kg 1 $cm^{2}$ = $10^{-4}$ $m^{2}$ so pressure = 2.249437605 kg per $10^{-4}$ $m^{2}$ pressure = 2.249437605 * $10^{4}$ kg per 1 $m^{2}$ pressure = 2.249437605 * $10^{4}$ kg / $m^{2}$ Rounding to 2 significant figures gives pressure = 2.2 * $10^{4}$ kg / $m^{2}$
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