General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Units of Measurement - Page 28: 34

Answer

1 link = 20.2 cm

Work Step by Step

100 links = 1 chain 1 link = 0.01 chain 1 furlong = 10 chains 10 chains = 1 furlong 1 chain = 0.1 furlong 0.01 chain = 0.001 furlong So 1 link = 0.001 furlong 8 furlongs = 1 mi 1 furlong = 0.125 mi 0.001 furlong = $1.25 * 10^{-4}$ mi So 1 link = $1.25 * 10^{-4}$ mi 0.62 mi = 1 km 0.62 mi = $10^{5}$ cm 1 mi = $10^{5}$ / 0.62 cm = 161290.3226 cm $1.25 * 10^{-4}$ mi = $1.25 * 10^{-4}$ * 161290.3226 cm = 20.16129033 cm So 1 link = 20.16129033 cm Rounding to 3 significant figures gives 20.2 cm
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.