## General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal

# Chapter 1 - Matter: Its Properties and Measurement - Exercises - Units of Measurement - Page 28: 34

1 link = 20.2 cm

#### Work Step by Step

100 links = 1 chain 1 link = 0.01 chain 1 furlong = 10 chains 10 chains = 1 furlong 1 chain = 0.1 furlong 0.01 chain = 0.001 furlong So 1 link = 0.001 furlong 8 furlongs = 1 mi 1 furlong = 0.125 mi 0.001 furlong = $1.25 * 10^{-4}$ mi So 1 link = $1.25 * 10^{-4}$ mi 0.62 mi = 1 km 0.62 mi = $10^{5}$ cm 1 mi = $10^{5}$ / 0.62 cm = 161290.3226 cm $1.25 * 10^{-4}$ mi = $1.25 * 10^{-4}$ * 161290.3226 cm = 20.16129033 cm So 1 link = 20.16129033 cm Rounding to 3 significant figures gives 20.2 cm

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