Chemistry: The Science in Context (4th Edition)

Published by W.W. Norton & Co.
ISBN 10: 0393124177
ISBN 13: 978-0-39312-417-0

Chapter 2 - Atoms, Molecules, and Ions: Matter Starts Here - Problems - Page 71: 79

Answer

(a) $BrO^-$ (b) $SO_4^{2-}$ (c) $IO_3^-$ (d) $NO_2^-$

Work Step by Step

For some of the oxoanions, we may have to refer to the internet for their formulas and charges. (a) Sodium (Na) has an oxidation number of $1+$ because it has a single electron in its outermost energy level that it can donate to another atom or ion. Hypobromite has a formula of $BrO^-$. Therefore, the compound formed between these two substances is $NaBrO$. (b) Potassium (K) has an oxidation number of $1+$ because it has a single electron in its outermost energy level that it can donate to another atom or ion. Sulfate has a formula of $SO_4^{2-}$. Therefore, the compound formed between these two substances is $K_2SO_4$. (c) Lithium (Li) has an oxidation number of $1+$ because it has a single electron in its outermost energy level that it can donate to another atom or ion. Iodate has a formula of $IO_3^-$. Therefore, the compound formed between these two substances is $LiIO_3$. (d) Magnesium (Mg) has an oxidation number of $2+$ because it has two electrons in its outermost energy level that it can donate to another atom or ion. Nitrite has a formula of $NO_2^-$. Therefore, the compound formed between these two substances is $Mg(NO_2)_2$.
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