Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises - Page 207: 5.73d

Answer

$H^o = -68.34kJ$

Work Step by Step

$H^o_f : SiCl_4(l) = -640.1 kj/mol$ $H^o_f : H_2O(l) = -285.83 kj/mol$ $H^o_f : SiO_2(s) = -910.9 kj/mol$ $H^o_f : HCl(g) = -92.3 kj/mol$ $SiCl_4(l) + 2H_2O(l) --> SiO_2(s) + 4HCl(g)$ $H^o = (-910.9 + 4*(-92.3)) - (-640.1 + 2*(-285.83)) $ $H^o = (-1280.1) - (-1211.76)$ $H^o = -68.34 kJ$
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