Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises - Page 207: 5.73a

Answer

$H^o = -196.6kJ$

Work Step by Step

$H^o_f : SO_2(g) = -296.9 kJ/mol$ $H^o_f : O_2(g) = 0 kJ/mol$ $H^o_f : SO_3(g) = -395.2 kJ/mol$ $2SO_2(g) + O_2(g) --> 2SO_3(g)$ $H^o = [2*(-395.2)] - [2*(-296.9) + 0]$ $H^o = [-790.4] - [-593.8]$ $H^o = -196.6kJ$
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