## Chemistry: The Central Science (13th Edition)

Balanced equation: $2HCH_3COO(aq) + Ba(OH)_2(aq) -> 2H_2O(l) + {Ba(CH_3COO)_2}(aq)$ Net ionic equation: $2HCH_3COO(aq) + 2OH^-(aq) -> 2H_2O(l) + 2{CH_3COO}^-(aq)$
1. Write the equation: $HCH_3COO(aq) + Ba(OH)_2(aq) -> H_2O(l) + {Ba(CH_3COO)_2}(aq)$ 2. Balance the equation: $2HCH_3COO(aq) + Ba(OH)_2(aq) -> 2H_2O(l) + {Ba(CH_3COO)_2}(aq)$ 3. Write the net ionic equation: $2HCH_3COO(aq) + Ba^{2+}(aq) + 2OH^-(aq) -> 2H_2O(l) + Ba^{2+}(aq) + 2{CH_3COO}^-(aq)$ 4. Remove the spectator ions: $2HCH_3COO(aq) + 2OH^-(aq) -> 2H_2O(l) + 2{CH_3COO}^-(aq)$