Answer
Balanced molecular equation:
${Al(OH)_3}{(s)} + 3 HNO_3(aq) -> 3 H_2O(l) + Al(NO_3)_3(aq)$
Net ionic equation:
$Al(OH)_3(s) + 3H^+(aq) -> 3H_2O(l) + Al^{3+}(aq) $
Work Step by Step
1. Complete the equation:
${Al(OH)_3}{(s)} + HNO_3(aq) -> H_2O(l) + Al(NO_3)_3(aq)$
2. Balance the equation:
${Al(OH)_3}{(s)} + 3 HNO_3(aq) -> 3 H_2O(l) + Al(NO_3)_3(aq)$
3. Write the ionic equation:
$Al(OH)_3(s) + 3H^+(aq) + {3NO_3}^-(aq) -> 3H_2O(l) + Al^{3+}(aq) +{3NO_3}^-(aq) $
4. Simplify it, by removing the ions that appears in both sides$(NO_3)^-$:
$Al(OH)_3(s) + 3H^+(aq) -> 3H_2O(l) + Al^{3+}(aq) $
