Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 4 - Reactions in Aqueous Solution - Exercises - Page 159: 4.51c


I is oxidized Cl is reduced

Work Step by Step

Cl2 + 2NaI --> I2 + 2NaCl Cl2 and I2 are in their elemental state so they have an oxidation state of 0. For NaI, Na has an oxidation state of +1 since it is an alkali metal so that means I must be I- and have an oxidation state of -1. Therefore, I goes from -1 on the left to 0 on the right. I loses electrons (is oxidized) For NaCl, Na is once again +1 since it is an alkali metal so Cl must be Cl- and -1 Therefore, Cl goes from 0 on the left to -1 on the right Cl gains electrons (is reduced)
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