Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 116: 3.61b


5.25 grams

Work Step by Step

From the coefficients in the equation, 2 moles of NaF are formed for 8 moles of HF reacted. If we have 0.5 moles HF then 0.5/8*2 = 0.125 moles of NaF are produced. Then we need the molar mass of NaF Na is 22.99 F is 18.997 22.99 + 18.997 = 42 g/mol If we have 0.125 mole then 0.125 mole * (42g/1mole) = 5.25 grams
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