Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 116: 3.61a


2.4 moles HF

Work Step by Step

From the left side of the equation we see: Na2SiO3 + 8HF --> Therefore, we need 8 moles of HF for each mole of Na2SiO3. If we have 0.3 mole Na2SiO3 then we would need 0.3*8 = 2.4 moles HF
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