## Chemistry: The Central Science (13th Edition)

First, we calculate the molecular mass of $Al(OH)_3$. Molecular mass of $Al(OH)_3$= (1x27)+(3x16)+(3x1) = 78 g/mol. How many moles of $Al(OH)_3$ have in 0.500 g? $\frac{0,500 g}{78g/mol}= 6,41\times10^{-6}$ mols de $Al(OH)_3$ This will react with $6,41\times10^{-6}\times3$ HCl = 0,0192 mol HCl. Now, we will find the molar mass of HCl: MM(HCl) = (1x1,008)+(1x35,45) = 36,5 g/mol Finally, the mass of 0.0192 mols = 0,0192 mols x 36,5 g/mol = 0,701 g HCl.