## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 2 - Atoms, Molecules, and Ions - Exercises - Page 77: 2.74e

#### Answer

$Co(HCO_3)_2$

#### Work Step by Step

This is an ionic compound, so the cation is what is listed first (Cobalt). The Roman numerals tell us that the cation has a charge of 2+. The anion is what is listed second (Hydrogen Carbonate). This anion has a formula of $HCO_3$, and a charge of -1. To have a neutral compound, there needs to be twice as many Hydrogen Carbonate molecules as Cobalt, hence $Co(HCO_3)_2$.

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