## Chemistry: The Central Science (13th Edition)

$V=1.0*10^{-29}m^3$
The formula for volume of a sphere is as follows: $V=\frac{4}{3}πr^3$ The radius is half the diameter, which is $2.7*10^{-8} cm$ or $2.7*10^{-8} cm*\frac{1m}{100cm}=2.7*10^{-10} m$ You convert your answer into meters because the question asks for the volume in $m^{3}$. The radius is then just $\frac{2.7*10^{-10} m}{2}=1.35*10^{-10}m$ Then use this value for $r$ in $V=\frac{4}{3}πr^3$. This gets you a $V=1.0306*10^{-29}m^3$. Rounding to the proper number of significant figures gets you $V=1.0*10^{-29}m^3$ your final answer