Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 2 - Atoms, Molecules, and Ions - Exercises - Page 75: 2.19b


$0.270nm · (m/ 1 x 10^6nm) · (1000mm/1m) = 0.000270 mm per atom$ $1.0 mm · (atom/ 0.000270mm) = 3.7x10^3 atoms Au$

Work Step by Step

The radius of a gold atom is 1.35 Angstroms. The diameter is 2.70. Use conversion factors to find the mm per atom. Divide 1.0mm by that number to determine how many atoms of gold can be lined up side by side.
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