Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 2 - Atoms, Molecules, and Ions - Exercises - Page 75: 2.20b


$2.2 \times 10^4 \space Rh \space atoms$

Work Step by Step

1. Identify the conversion factors: - Meters to centimeters: $\frac{100 \space cm}{1 \space m }$ - $\mu m$ to Meters : $\frac{10^{-6} \space m}{1 \space \mu m }$ ** If we divide the length of the line of atoms by their diameters, we will get the total number of atoms. $\frac{6.0 \space \mu m \space }{2.7 \times 10^{-8} \space cm \space } \times \frac{100 \space cm}{1 \space m } \times \frac{10^{-6} \space m}{1 \space \mu m } = 2.2 \times 10^4 \space Rh \space atoms$
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