Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 17 - Additional Aspects of Aqueous Equilibria - Additional Exercises - Page 772: 17.99b

Answer

$K = 8.037 \times 10^{-13}$

Work Step by Step

1. We can calculate the K by using this formula: $K = K_b * K_{ps}$ 2. Find the $K_b$ of $CO_3^{2-}$, using the $K_a$ of $H{CO_3}^-$: $Ka * Kb = Kw$ $Kb = \frac{10^{-14}}{5.6 \times 10^{-11}}$ $Kb = 1.786 \times 10^{-4}$ 3. Calculate K: $K = 1.786 \times 10^{-4} * 4.5\times 10^{-9}$ $K = 8.037 \times 10^{-13}$
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