## Chemistry: The Central Science (13th Edition)

$BaCrO_4$ has a higher solubility.
$K_{ps}: BaCrO_4 = 2.1 \times 10^{-10}$ $K_{ps}: PbCO_3 = 7.4 \times 10^{-14}$ Since the Kps of $BaCrO_4$ is higher, it is more soluble. The Kps values are given in the book.