Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 17 - Additional Aspects of Aqueous Equilibria - Additional Exercises - Page 772: 17.98b

Answer

$BaCrO_4$ has a higher solubility.

Work Step by Step

$K_{ps}: BaCrO_4 = 2.1 \times 10^{-10}$ $K_{ps}: PbCO_3 = 7.4 \times 10^{-14}$ Since the Kps of $BaCrO_4$ is higher, it is more soluble. The Kps values are given in the book.
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