Answer
$BaCrO_4$ has a higher solubility.
Work Step by Step
$K_{ps}: BaCrO_4 = 2.1 \times 10^{-10}$
$K_{ps}: PbCO_3 = 7.4 \times 10^{-14}$
Since the Kps of $BaCrO_4$ is higher, it is more soluble.
The Kps values are given in the book.
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