Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 17 - Additional Aspects of Aqueous Equilibria - Additional Exercises - Page 772: 17.99a

Answer

Approximately $6.708 \times 10^{-5} M$.

Work Step by Step

1. Write the Kps equation: $K_{ps} = [Ca^{+2}]\times[CO_3^{-2}]$ $[Ca^{+2}] = [CO_3^{-2}] = x$ $K_{ps} = x^2$ 2. Find the value of x: $4.5 \times 10^{-9} = x^2$ $x = \sqrt {4.5 \times 10^{-9}}$ $x \approx 6.708 \times 10^{-5}M $
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