Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 13 - Properties of Solutions - Exercises - Page 568: 13.43b



Work Step by Step

Molarity is defined as moles solute per liter of solution. First, we must find the number of moles of LiClO4*3H2O. We will first need the molar mass from the periodic table: $160.44\;\frac{g}{mol}\;LiClO_4\bullet3H_2O$ Next, convert to moles: $(22.4\;g\;LiClO_4\bullet3H_2O)\times(\;\frac{1\;mol}{160.44\;g})$ $0.1396\;mol$ Next, convert to liters of solution: $125\;mL = 0.125\;L$ Now, utilize molarity formula $M=\frac{0.1396\;mol\;solute}{0.125\;L\;solution}$ $1.12\;M\;LiClO_4\bullet3H_2O$
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