Answer
$1.12\;M\;LiClO_4\bullet3H_2O$
Work Step by Step
Molarity is defined as moles solute per liter of solution.
First, we must find the number of moles of LiClO4*3H2O.
We will first need the molar mass from the periodic table:
$160.44\;\frac{g}{mol}\;LiClO_4\bullet3H_2O$
Next, convert to moles:
$(22.4\;g\;LiClO_4\bullet3H_2O)\times(\;\frac{1\;mol}{160.44\;g})$
$0.1396\;mol$
Next, convert to liters of solution:
$125\;mL = 0.125\;L$
Now, utilize molarity formula
$M=\frac{0.1396\;mol\;solute}{0.125\;L\;solution}$
$1.12\;M\;LiClO_4\bullet3H_2O$
