Answer
0.0146 M
Work Step by Step
We have 0.540g of Mg(NO3)2 and in 250mL. To find the molarity, we need the moles of Mg(NO3)2 per liter so we need the molar mass of Mg(NO3)2 to find the moles:
Mg is 24.3 g/mol
N is 14 g/mol
O is 16 g/mol
24.3 + (14 + 3*16) * 2 = 148.3 g/mol
Then we have 0.540g * (1mol/148.3g) = 0.0036 moles
Then we have 250mL, or 0.250L so the molarity is 0.0146 M