Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 13 - Properties of Solutions - Exercises - Page 568: 13.42b

Answer

$4.67\%$ $C_{6}H_{5}OH$

Work Step by Step

Formula: mass percent = $\frac{mass solute}{mass solution}$ x 100 Given: mass of solute (phenol) = 20.8 g $C_{6}H_{5}OH$ mass of solvent (ethanol) = 425 g $CH_{3}CH_{2}OH$ mass of solution = mass of solute + mass of solvent Substitution of values: mass of solution = 20.8 g $C_{6}H_{5}OH$ + 425 g $CH_{3}CH_{2}OH$ = 445.8 g mass percent = $\frac{20.8 g C_{6}H_{5}OH }{445.8 g solution}$ x 100 mass percent $= 4.6657 \approx 4.67\% C_{6}H_{5}OH$
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