Chemistry: Principles and Practice (3rd Edition)

Published by Cengage Learning
ISBN 10: 0534420125
ISBN 13: 978-0-53442-012-3

Chapter 7 - Electronic Structure - Questions and Exercises - Exercises - Page 285: 7.34



Work Step by Step

E=hν = hc/λ h = $6.626\times10^{-34}Js$ c = $2.997925\times10^{8}ms^{-1}$ λ = 640 nm = $640\times10^{-9}m$ E = $\frac{6.626\times10^{-34}Js\times2.997925\times10^{8}ms^{-1}}{640\times10^{-9}m}$ = $3.1\times10^{-19}J$
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