Chemistry: Principles and Practice (3rd Edition)

Published by Cengage Learning
ISBN 10: 0534420125
ISBN 13: 978-0-53442-012-3

Chapter 7 - Electronic Structure - Questions and Exercises - Exercises - Page 285: 7.29


a) $3.73\times10^{-19}J$ b) $2.68\times10^{18}s^{-1}$

Work Step by Step

a) E=hν = hc/λ h = $6.626\times10^{-34}Js$ c = $2.997925×10^{8}ms^{-1}$ λ = 533 nm = $533\times10^{-9}m$ E = $\frac{6.626\times10^{-34}Js\times2.997925×10^{8}ms^{-1}}{533\times10^{-9}m}$ = $3.73\times10^{-19}J$ b) Power of the laser = $1 Js^{-1}$ Energy of one photon = $3.73\times10^{-19}J$ Number of photons emitted = $\frac{1Js^{-1}}{3.73\times10^{-19}J}$ = $2.68\times10^{18}s^{-1}$
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