## Chemistry: Principles and Practice (3rd Edition)

517 m or $5.17×10^{11}nm$
Given that the frequency, ν= 580 kHz= $580×10^{3}s^{-1}$. Recall the relation λ= c/ν where λ is the wavelength and c is the speed of light. Then, λ= $\frac{3.00×10^{8}m/s}{580×10^{3}s^{-1}}$= 517 m = $5.17×10^{11}×10^{-9}m$=$5.17×10^{11}nm$ (as the prefix nano= $10^{-9}$)