Chemistry: Principles and Practice (3rd Edition)

Published by Cengage Learning
ISBN 10: 0534420125
ISBN 13: 978-0-53442-012-3

Chapter 7 - Electronic Structure - Questions and Exercises - Exercises - Page 285: 7.23


517 m or $5.17×10^{11}nm$

Work Step by Step

Given that the frequency, ν= 580 kHz= $580×10^{3}s^{-1}$. Recall the relation λ= c/ν where λ is the wavelength and c is the speed of light. Then, λ= $\frac{3.00×10^{8}m/s}{580×10^{3}s^{-1}}$= 517 m = $5.17×10^{11}×10^{-9}m$=$ 5.17×10^{11}nm$ (as the prefix nano= $10^{-9}$)
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