Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 9 - Liquids, Solids, and Materials - Questions for Review and Thought - Topical Questions - Page 421a: 17


73.4 kJ

Work Step by Step

Number of moles of $C_{4}H_{10}$ $=\frac{190.\,g}{58.12\,g/mol}=3.27\,mol$ 22.44 kJ is needed to vaporize 1 mol of $C_{4}H_{10}$. $\implies$ Heat transfer required q= $3.27\,mol\times22.44\,kJ/mol=73.4\,kJ$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.