## Chemistry: The Molecular Science (5th Edition)

Number of moles of $C_{4}H_{10}$ $=\frac{190.\,g}{58.12\,g/mol}=3.27\,mol$ 22.44 kJ is needed to vaporize 1 mol of $C_{4}H_{10}$. $\implies$ Heat transfer required q= $3.27\,mol\times22.44\,kJ/mol=73.4\,kJ$