Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 9 - Liquids, Solids, and Materials - Questions for Review and Thought - Topical Questions - Page 421a: 15


180.5 KJ

Work Step by Step

We use stoichiometry to find: $$\frac{1000 g}{1} \frac{ mol}{137.37 g} \frac{24.8 KJ}{mol}= 180.5 KJ$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.