Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 9 - Liquids, Solids, and Materials - Questions for Review and Thought - Topical Questions - Page 421a: 15

Answer

180.5 KJ

Work Step by Step

We use stoichiometry to find: $$\frac{1000 g}{1} \frac{ mol}{137.37 g} \frac{24.8 KJ}{mol}= 180.5 KJ$$
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