Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 9 - Liquids, Solids, and Materials - Questions for Review and Thought - Topical Questions - Page 421a: 16


233 KJ

Work Step by Step

We use stoichiometry to find: $$ \frac{250 ml}{1} \times \frac{.787 g}{ml} \times \frac{mol}{32.04g} \times \frac{38.0 KJ } {mol} =233 KJ$$
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