## Chemistry: The Molecular Science (5th Edition)

$K_{sp} (HgI_2) = (3.2 \times 10^{-29})$
1. Write the $K_{sp}$ expression: $HgI_2(s) \lt -- \gt 1Hg^{2+}(aq) + 2I^{-}(aq)$ $K_{sp} = [Hg^{2+}]^ 1[I^{-}]^ 2$ 2. Determine the ions concentrations: $[Hg^{2+}] = [HgI_2] * 1 = [2 \times 10^{-10}] * 1 = 2 \times 10^{-10}M$ $[I^{-}] = [HgI_2] * 2 = 4 \times 10^{-10}M$ 3. Calculate the $K_{sp}$: $K_{sp} = (2 \times 10^{-10})^ 1 \times (4 \times 10^{-10})^ 2$ $K_{sp} = (2 \times 10^{-10}) \times (1.6 \times 10^{-19})$ $K_{sp} = (3.2 \times 10^{-29})$