# Chapter 12 - Chemical Equilibrium - Problem Solving Practice 12.1 - Page 531: c

$$K_c = \frac{[CO][H_2]^3}{[CH_4][H_2O]}$$

#### Work Step by Step

$$K_c = \frac{[Products]}{[Reactants]}$$ $$K_c = \frac{[CO][H_2]^3}{[CH_4][H_2O]}$$ ** Since there are 3 $H_2$ molecules in the balanced equation, we have to put in a "3" as the exponent of $[H_2]$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.