Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 12 - Chemical Equilibrium - Problem Solving Practice 12.1 - Page 531: c

Answer

$$K_c = \frac{[CO][H_2]^3}{[CH_4][H_2O]} $$

Work Step by Step

$$K_c = \frac{[Products]}{[Reactants]}$$ $$K_c = \frac{[CO][H_2]^3}{[CH_4][H_2O]} $$ ** Since there are 3 $H_2$ molecules in the balanced equation, we have to put in a "3" as the exponent of $[H_2]$.
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