Answer
$$K_c = [CO_2]$$
Work Step by Step
$$K_c = \frac{[Products]}{[Reactants]}$$
$$K_c = \frac{[CO_2]}{1} = [CO_2]$$
** Since $CaCO_3$ and $CaO$ are pure solids, we do not put them in the equation for $K_c$.
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 12 - Chemical Equilibrium - Problem Solving Practice 12.1 - Page 531: a
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