Answer
$$K_c = \frac{[H_2]}{[HCl]} $$
Work Step by Step
$$K_c = \frac{[Products]}{[Reactants]}$$
$$K_c = \frac{[H_2]}{[HCl]} $$
** Since $LiH$ and $LiCl$ are pure solids, we do not put them in the equation for $K_c$.
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