Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 12 - Chemical Equilibrium - Exercise 12.1 - Concentrations of Pure Solids and Liquids - Page 526: c


Concentration of water: 55.4 mol/L

Work Step by Step

Molar mass of water $(H_2O)$ = 1.01 * 2 + 16.0 = 18.0 g/mol $$\frac{0.998 \space g}{1 \space mL} \times \frac{1000 \space mL}{1 \space L} \times \frac{1 \space mol}{18.0 \space g} = 55.4 \space mol/L$$
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