Chemistry: The Molecular Science (5th Edition)

by Moore, John W.; Stanitski, Conrad L.

Published by Cengage Learning

ISBN 10: 1285199049

ISBN 13: 978-1-28519-904-7

Chapter 12 - Chemical Equilibrium - Exercise 12.1 - Concentrations of Pure Solids and Liquids - Page 526: c

Answer

Concentration of water: 55.4 mol/L

Work Step by Step

Molar mass of water $(H_2O)$ = 1.01 * 2 + 16.0 = 18.0 g/mol $$\frac{0.998 \space g}{1 \space mL} \times \frac{1000 \space mL}{1 \space L} \times \frac{1 \space mol}{18.0 \space g} = 55.4 \space mol/L$$

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