Chemistry: The Molecular Science (5th Edition)

by Moore, John W.; Stanitski, Conrad L.

Published by Cengage Learning

ISBN 10: 1285199049

ISBN 13: 978-1-28519-904-7

Chapter 12 - Chemical Equilibrium - Exercise 12.1 - Concentrations of Pure Solids and Liquids - Page 526: d

Answer

Concentration of gold: $98.07 \space mol/L$

Work Step by Step

Molar mass of gold $(Au)$ =197.0 g/mol $$\frac{19.32 \space g}{1 \space mL} \times \frac{1000 \space mL}{1 \space L} \times \frac{1 \space mol}{197.0 \space g} = 98.07 \space mol/L$$

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