Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 12 - Chemical Equilibrium - Exercise 12.1 - Concentrations of Pure Solids and Liquids - Page 526: a


Concentration of aluminum = 100. mol/L

Work Step by Step

$$\frac{2.70 \space g}{1 \space mL} \times \frac{1000 \space mL}{1 \space L} \times \frac{1 \space mol}{26.98 \space g} = 100. \space mol/L$$
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