#### Answer

0.0186 M/min

#### Work Step by Step

Average rate=$\frac{1}{2}\times\frac{\Delta [NH_{3}]}{\Delta t}$
$=\frac{1}{2}\times\frac{0.815M-0.257M}{15.0 min}= 0.0186 M/min$

Published by
Cengage Learning

ISBN 10:
1285199049

ISBN 13:
978-1-28519-904-7

0.0186 M/min

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