Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 11 - Chemical Kinetics: Rates of Reactions - Questions for Review and Thought - Topical Questions - Page 523a: 18c

Answer

0.0186 M/min

Work Step by Step

Average rate=$\frac{1}{2}\times\frac{\Delta [NH_{3}]}{\Delta t}$ $=\frac{1}{2}\times\frac{0.815M-0.257M}{15.0 min}= 0.0186 M/min$
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