Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 11 - Chemical Kinetics: Rates of Reactions - Questions for Review and Thought - Topical Questions - Page 523a: 19b


The rate will decrease to one-fourth of the original rate.

Work Step by Step

$Rate= k[A]^{2}$ When the concentration of A is halved, New Rate=$ (\frac{1}{2})^{2}\times k[A]^{2}= \frac{1}{4}(k[A]^{2}).$
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