Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 11 - Chemical Kinetics: Rates of Reactions - Questions for Review and Thought - Topical Questions - Page 523a: 19a

Answer

The rate will increase 9 times.

Work Step by Step

$Rate= k[A]^{2}$ When the concentration of A is tripled, $Rate= 3^{2}\times k[A]^{2}= 9(k[A]^{2}).$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.