Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 7 - Quantum Mechanics and The Atom - Exercises - Page 330: 43

Answer

$1.03\times10^{16}$ photons

Work Step by Step

Total energy= $3.85\,mJ=3.85\times10^{-3}\,J$ Energy of one photon= $\frac{hc}{\lambda}$ $=\frac{(6.626\times10^{-34}\,J\cdot s)(3.00\times10^{8}\,m/s)}{532\times10^{-9}\,m}$ $=3.736466\times10^{-19}\,J$ Number of photons= $\frac{\text{Total energy}}{\text{Energy of one photon}}$ $=\frac{3.85\times10^{-3}\,J}{3.736466\times10^{-19}\,J}$ $=1.03\times10^{16}$
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