Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 7 - Quantum Mechanics and The Atom - Exercises - Page 330: 39

Answer

(a) $4.74\times10^{14}\,Hz$ (b) $5.96\times10^{14}\,Hz$ (c) $5.8\times10^{18}\,Hz$

Work Step by Step

Using the relation $\nu=\frac{c}{\lambda}$ where $c$ is the speed of light, we have (a) Frequency $\nu=\frac{3.00\times10^{8}m/s}{632.8\,nm}$ $=\frac{3.00\times10^{8}\,m/s}{632.8\times10^{-9}\,m}$ $=4.74\times10^{14}\,Hz$ (b) $\nu=\frac{3.00\times10^{8}\,m/s}{503\times10^{-9}\,m}$ $=5.96\times10^{14}\,Hz$ (c) $\nu=\frac{3.00\times10^{8}\,m/s}{0.052 \times10^{-9}\,m}$ $=5.8\times10^{18}\,Hz$
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