Answer
(a) $6.639\times10^{-26}\,J$
(b) $7.09\times10^{-28}\,J$
(c) $5.537\times10^{-25}\,J$
Work Step by Step
Using the relation $E=h\nu$, we have
(a) $E=(6.626\times10^{-34}\,J\cdot s)(100.2\times10^{6}\,s^{-1})$
$=6.639\times10^{-26}\,J$
(b) $E=(6.626\times10^{-34}\,J\cdot s)(1070\times10^{3}\,s^{-1})$
$=7.09\times10^{-28}\,J$
(c) $E=(6.626\times10^{-34}\,J\cdot s)(835.6\times10^{6}\,s^{-1})$
$=5.537\times10^{-25}\,J$
