Answer
The mass of sucrose is equal to 402 g.
Work Step by Step
1. Find the number of moles:
$Concentration(M) = \frac{n(mol)}{V(L)}$
$0.758 = \frac{n(mol)}{1.55}$
$0.758 * 1.55 = n(mol)$
$1.175 moles = n(mol)$
2. Determine the molar mass of this compound $(C_{12}H_{22}O_{11})$:
12.01* 12 + 1.008* 22 + 16.00* 11 = 342.30g/mol
3. Calculate the mass
$mm(g/mol) = \frac{mass(g)}{n(mol)}$
$mm(g/mol) * n(mol) = mass(g)$
$ 342.30 * 1.175 = mass(g)$
$402 = mass(g)$
