## Chemistry: Molecular Approach (4th Edition)

1. Find the number of moles: $Concentration(M) = \frac{n(mol)}{V(L)}$ $0.758 = \frac{n(mol)}{1.55}$ $0.758 * 1.55 = n(mol)$ $1.175 moles = n(mol)$ 2. Determine the molar mass of this compound $(C_{12}H_{22}O_{11})$: 12.01* 12 + 1.008* 22 + 16.00* 11 = 342.30g/mol 3. Calculate the mass $mm(g/mol) = \frac{mass(g)}{n(mol)}$ $mm(g/mol) * n(mol) = mass(g)$ $342.30 * 1.175 = mass(g)$ $402 = mass(g)$