## Chemistry: Molecular Approach (4th Edition)

44.6 g of $KBr$
- Convert the volume to liters: $250.0 mL \times \frac{1L}{10^3L} = 0.2500 L$ 1. Find the number of moles: $Concentration(M) = \frac{n(mol)}{V(L)}$ $1.5 = \frac{n(mol)}{0.2500}$ $1.5 * 0.25000 = n(mol)$ $0.375 moles = n(mol)$ 2. Determine the molar mass of this compound (KBr): 39.1* 1 + 79.9* 1 = 119.0g/mol 3. Calculate the mass $mm(g/mol) = \frac{mass(g)}{n(mol)}$ $mm(g/mol) * n(mol) = mass(g)$ $119 * 0.375 = mass(g)$ $44.6 = mass(g)$