Answer
The volume of that $KCl$ solution is equal to 221 mL.
Work Step by Step
1. Determine the molar mass of this compound (KCl):
39.10* 1 + 35.45* 1 = 74.55g/mol
2. Calculate the number of moles:
$mm(g/mol) = \frac{mass(g)}{n(mol)}$
$ 74.55 = \frac{2.54}{n(mol)}$
$n(mol) = \frac{2.54}{ 74.55}$
$n(mol) = 0.0342$
3. Find the volume:
$Concentration(M) = \frac{n(mol)}{V(L)}$
$0.155 = \frac{0.0342}{V(L)}$
$V(L) = \frac{0.0342}{0.155}$
$V(L) = 0.221 $
4. Convert that number to mL:
1 L = $1000$ mL
$0.221$ L = $0.221 \times 1000$ mL = $221$ mL
