## Chemistry: Molecular Approach (4th Edition)

The anion in this compound is acetate ($C_2H_3O_2^-$), which has a -1 charge. But the compound is neutral. So, the cation lead ($Pb^{2+}$) has a +2 charge to make the compound neutral. $Pb$ shows variable valencies, so the name of the compound is $lead(II) acetate$. So, the correct answer is (b)