## Chemistry: Molecular Approach (4th Edition)

a. $NaOH$ is a base. $$NaOH(aq) \longrightarrow Na^+(aq) + OH^-(aq)$$ b. $H_2SO_4$ is an acid. $$H_2SO_4(aq) \longrightarrow HS{O_4}^-(aq) + H^+$$ c. $HBr$ is an acid. $$HBr(aq) \longrightarrow H^+(aq)+ Br^-(aq)$$ d. $Sr(OH)_2$ is a base. $$Sr(OH)_2(aq) \longrightarrow Sr^{2+}+2OH^-(aq)$$
1. According to Arrhenius' definition, an acid is a substance that produces $H^+$ ions in aqueous solution. Therefore, they must have a disponible $H^+$ in their structures, like $H_2SO_4$ and $HBr$. 2. According to the same scientist, bases are substances that produce $OH^-$ ions in aqueous solution. Therefore, they must have a disponible $OH^-$ like $NaOH$ and $Sr(OH)_2$. 3. The chemical equation is basically the substance ionizing, separating their ions.