Answer
See the explanation
Work Step by Step
For the molecules in Exercises 21 and 22:
The expected hybridization of the central atom is sp3.
In Exercise 21, the molecule is methane (CH4). The carbon atom in the center is bonded to four hydrogen atoms, forming a tetrahedral arrangement. This requires the carbon atom to have an sp3 hybridization, where the s orbital and three p orbitals combine to form four equivalent sp3 hybrid orbitals.
In Exercise 22, the molecule is ammonia (NH3). The nitrogen atom in the center is bonded to three hydrogen atoms, also forming a tetrahedral arrangement. This requires the nitrogen atom to have an sp3 hybridization.
.
