Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Let's Review: The Tools of Quantitative Chemistry - Study Questions - Page 43e: 59


$0.927\ mm$

Work Step by Step

Mass of mercury: $3.416-3.263=0.153\ g$ Density of mercury: 13.546 g/cm³, so the volume is: $V=m/\rho=0.0113\ cm^3$ Length of the tube $16.75\ mm = 1.675\ cm$ Volume of the tube: $V=\pi r^2 L$, so the radius is: $r=0.0463\ cm=0.463\ mm$ So the diameter (twice the radius) is $0.927\ mm$.
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